Question

a cyclist driving at 36 km/hr stop his cycle in 2 sec by applying brakes find retardation

Answer 1

$\textbf{Answer:}$

We use the equation of motion,
v = u - a × t.

Given in the question,

Retardation (a) = ?
Time = 2 sec
Final velocity (v) = 0

Initial velocity (u)
= 36 km/h × (5/18)
= 10 m/s

Now, for retardation or deceleration,
v = u - a × t
0 = 10 - a × 2
a = 10 / 2
a = 5 m/s²
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Answer 2

Hiya folks!!

Here's your answer

U=36km/hr= 36*5/18
= 10m/s
V=0
T= 2 seconds

Using, v= u+at
0= 10+2a
2a= 0-10
a= -10/2
a= -5 m/s^2

Hope this helps you

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