Physics, asked by shubhamgupta7258, 11 months ago

A cyclist driving at 5 metre per second pics a velocity of 10 metre per second over a distance of 50 metre calculate acceleration and time in which day cyclist picks up above velocity

Answers

Answered by yashsri1992
14

Answer:

initial velocity of cyclist=5m/s

Final Velocity of cyclist=10m/s

speed=distnace/time

time=distance/speed

time=50/5

time=10sec

after 10 sec cyclist accelerates to 10m/s

acceleration =v-u/t

10-5/10

5/10

.5m/s^2 is the acceleration

Answered by shivangi4375
22

Try to do the (ii) part yourself , I have given the identity to solve.

Hope you will not get any problem.......

Attachments:
Similar questions