A cyclist driving at 5 metre per second pics a velocity of 10 metre per second over a distance of 50 metre calculate acceleration and time in which day cyclist picks up above velocity
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Answer:
initial velocity of cyclist=5m/s
Final Velocity of cyclist=10m/s
speed=distnace/time
time=distance/speed
time=50/5
time=10sec
after 10 sec cyclist accelerates to 10m/s
acceleration =v-u/t
10-5/10
5/10
.5m/s^2 is the acceleration
Answered by
22
Try to do the (ii) part yourself , I have given the identity to solve.
Hope you will not get any problem.......
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