Question

a cyclist driving at 5m/s picks a velocity of 10 m/s over a distance of 50 m calculate time in which the cyclist pick up the above velocity ​

Answer 1

Answer:

u=5m/s

v=10m/s

s=50m

t=?

V2 -u2 = 2as

100-25 = 100a

75=100a

a = 0.75m/s2

v= u+at

10 = 5+ 0.75×t

5= 0.75×t

t = o.6s

Answer 2

Given

Cyclist driving a cycle

at u=5m/s

V=10m/s

S=50m

To find

time to pick up the velocity

Solution

From equation of motion

• V²=u²+2as

Putting the value

=>100=25+100a

=>75=100a

$\therefore\:a=\frac{75}{100}$

$\therefore\:a=\sf{0.75}$

Now finding for t

• V=u+at

=>10=5+0.75t

=>5=0.75t

$\therefore\:t=\frac{5}{0.75}$

$\therefore\:t=\sf{6.6sec}$