a cyclist driving at 5m/s picks a velocity of 10m/s over distance of 50 m calculate -1) Acceler ,2) time in which cyclist picks up the above velocity l.
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Answered by
129
U= 5m/s
V=10m/s
S=50m
We know,
2as=v^2-u^2
A=(10×10)-(5×5)/2×50
A=75/100
A=0.75m/s2
We know
A=v-u/t
75/100×t=10-5
T=3.75 seconds
V=10m/s
S=50m
We know,
2as=v^2-u^2
A=(10×10)-(5×5)/2×50
A=75/100
A=0.75m/s2
We know
A=v-u/t
75/100×t=10-5
T=3.75 seconds
Answered by
39
Answer:
the answer is.....
the answer is.....(i) a = 0.75 m/s^2
the answer is.....(i) a = 0.75 m/s^2 and
the answer is.....(i) a = 0.75 m/s^2 and(ii) t = 6.66 secs
Explanation:
see...the explanation is above.... okay..... thank you....
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