Question

a cyclist driving at 5m/s picks a velocity of 10m/s over distance of 50 m calculate -1) Acceler ,2) time in which cyclist picks up the above velocity l.

Answer 1

U= 5m/s
V=10m/s
S=50m

We know,

2as=v^2-u^2

A=(10×10)-(5×5)/2×50

A=75/100

A=0.75m/s2


We know

A=v-u/t

75/100×t=10-5

T=3.75 seconds

Answer 2

Answer:

the answer is.....

the answer is.....(i) a = 0.75 m/s^2

the answer is.....(i) a = 0.75 m/s^2 and

the answer is.....(i) a = 0.75 m/s^2 and(ii) t = 6.66 secs

Explanation:

see...the explanation is above.... okay..... thank you....