A cyclist driving at 90 km/h is slowed down to 36 km/h in 5 sec. Calculate retardation
1) -3 m/s^2
2) 3 m/s^2
3) -10.8 m/s^2
4) 10.8 m/s^2
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ANSWER :
1). -3 m/s²
EXPLANATION :
INITIAL VELOCITY (u) = 90 km/h = 25 m/s
FINAL VELOCITY (v) = 36 km/h = 10 m/s
time (t) = 5 seconds
we know that,
a=(v-u)/t.....(i)
hence put the above values in (i).
a=(10-25)/5
a=-15/5
a=-3 m/s² (required answer)
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