A cyclist for t second at a speed of 3ms and then for the same time at a speed of 5ms along a straight road due north what is the average speed of the cyclist
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Answer:
4m/s
Explanation:
time= t second
speed'1= 3m/s
speed'2=5m/s
distance'1= speed x t
= 3xt= 3t metre/second
distance'2= speed x time
=5 x t= 5t metre/second
average velocity= Total distance covered/total time taken
=(5t + 3t/ t + t)m/s
=(8t / 2t) m/s
=4m/s
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