Question

A cyclist goes 3 km East.Now,it turns right and goes another 4 km.How far is he from its starting point?
plz tell ​

Answer 1

Answer:

He is 5km far from his starting point.

Step-by-step explanation:

The distance covered by the cyclist in east direction = 3km

That in South direction (when he turns right) = 4km

Thus using pythagorus theorm the distance of him from his initial point

$= \sqrt{ {3}^{2} + {4}^{2} } \\ = \sqrt{9 + 16} \\ = \sqrt{25} = 5 \: km$

Answer 2

Answer:

Hope that helps.

Also sorry for the terrible handwriting, hope you understand the solution

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