Physics, asked by mysoresudhirkumar53, 8 months ago

A cyclist goes around a circular track
once every 2 minutes.
If radius of the
circular tract is 110m, calculate
the speed of cyclist , and also find the Average velocity?

Answers

Answered by Anonymous
2

\color{red}\large\underline{\underline{Question:}}

\textit{A cyclist goes around a circular track}\textit{once every two minutes .if the radius}\textit{of the circular track is 110m,}\textit{calculate </p><p>the speed of cyclist ,}\textit{and also find the Average velocity?}

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\color{purple}\large\underline{\underline{To\:Find:}}

  • \mathtt{The\:speed\:of\:the\:cyclist}
  • \mathtt{The\:Average\:speed\:of\:the\:cyclist}

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\color{blue}\large\underline{\underline{Given:}}

  • \mathtt{Time \rightarrow 2min = 120sec}
  • \mathtt{Distance \rightarrow \dfrac{4840}{7}m}
  • \mathtt{Displacement \rightarrow 0}

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\color{magenta}\large\underline{\underline{We\: know:}}

  • \mathtt{Speed = \dfrac{Distance}{time}}
  • \mathtt{Average\:velocity = \dfrac{Total\: Displacement}{Total\:time}}

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\color{blue}\large\underline{\underline{Concept:}}

  • \textsf{First , we have to change the time from minutes to secs.}
  • \textsf{Since, it is a circular track the displacement will be zero}

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\color{orange}\large\underline{\underline{Solution:}}

\underline{Speed:}

we know,

\mathtt{Speed = \dfrac{Distance}{time}}

\mathtt{\Rightarrow Speed = \dfrac{\dfrac{4840}{7}}{120}m\:s^{-1}}

\mathtt{\Rightarrow Speed = \dfrac{4840}{120 \times 7}m\:s^{-1}}

\mathtt{\Rightarrow Speed = 5.76m\:s^{-1}}

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\underline{Average\:Velocity:}

we know,

\mathtt{Average\:velocity = \dfrac{Total\: Displacement}{Total\:time}}

\mathtt{\Rightarrow Average\:velocity = \dfrac{0}{120}}

\mathtt{\Rightarrow Average\:velocity = 0}

\text{Here the displacement is zero as} \text{the cyclists reached the initial position}

Answered by govind1348
1

Answer:

Explanation:

Speed= total distance/total time

Since he completes his round trip in 2 minutes

Displacement is zero but distance = perimeter (since it is a round trip) so dist= 2pi r

=2 pi 110= 220 pi = 220×3.14=660(approx)

Speed = total distance/total time

= 660/2×60=660/120 = 5.5 m/s

And average velocity = 0 since displacement in round trip is zero.

Thank you for you time.

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