A cyclist goes from a place P to Q; first at 4 km/h and later at 5 km/h in 1 hour 24 minutes altogether. If the distances covered in the first and second part of the journey are in the ratio 2 : 1, when did the cyclist change his speed after start?
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Answer:
1 hr
Step-by-step explanation:
total distance= 3x
given, 2:1 =
2x km at 4 km per hr
x km at 5km per hr
time= distance/speed
2x/4 + x/5 = 1 + 24/60
solve and u get,
x = 2
total distance= 3x= 3 x 2= 6 km
changes his peed after 4 km
so, 4/4 = 1hr
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