A cyclist goes once a round a circular track of diameter 1 metres in 50minutes calculate it's speed.
Answers
Answered by
1
Radius=diameter/2=0.5 m
Total distance=2×pi×radius
=>x=2×22/7×1/2
=>x=22/7
Total time=50 min= 3000 sec
So, speed=22/(3000×7)=22/21000 m/s
PLZ MARK IT AS BRAINLIEST..
Total distance=2×pi×radius
=>x=2×22/7×1/2
=>x=22/7
Total time=50 min= 3000 sec
So, speed=22/(3000×7)=22/21000 m/s
PLZ MARK IT AS BRAINLIEST..
Answered by
1
Diameter of track = 1m
Radius of track = D/2 = 1/2 m
Circumference of track -
2πr
= 2 × 22/7 × 1/2
or, 22/7 m
So, the distance which cyclist covers in 50minutes is 22/7 m.
50 minutes = (50×60)seconds = 3000seconds.
So, speed = distance/Time
= 22/7 ÷ 3000
=22/7 × 1/3000
=22/21000 m/s
Answer) speed of cyclist = 22/21000 m/s
Radius of track = D/2 = 1/2 m
Circumference of track -
2πr
= 2 × 22/7 × 1/2
or, 22/7 m
So, the distance which cyclist covers in 50minutes is 22/7 m.
50 minutes = (50×60)seconds = 3000seconds.
So, speed = distance/Time
= 22/7 ÷ 3000
=22/7 × 1/3000
=22/21000 m/s
Answer) speed of cyclist = 22/21000 m/s
Similar questions
Computer Science,
8 months ago
English,
1 year ago
Physics,
1 year ago
Math,
1 year ago
Physics,
1 year ago