a cyclist has to cover journey of 117 km. in 6 1/2 hours. after 2 3/3 h he finds out that he has travelled 57 km. find the decrease in speed he has to make in order to arrive at his destination on time.
Answers
Step-by-step explanation:
1. In one hour 18 km.
2. In (2 3/3) hrs 3 hrs means 54 km but he is travelling 3 km extra which is 57
3.Remaining distance is equal to 60 km.
4.So he should travel at (60/3.5) kmph. it means 17.14 km/hr should be the speed.
5. Previous speed is 18. Now is 17.1 so speed decreased by 0.9 km/hr. Check If wrong any one comment please
Hope it helps
4.72kwe won't divide 117km with 6hours 30 minutes (6.5) considering it will give us rhe average speed which is 18km we need to find the difference in speed so first speed=distance÷time we will calculate the speed of the part of the journey he travelled 57km÷ 2.75hours which will give us 20.72km/h then we will subtract the time taken from the whole journey 6hours 30 minutes- 2hours 42minutes= 3 hours 45minutes and distance left 117-57= 60km and then again find the speed 60÷3.75h =16km/h now we will simply subtract them to find the difference in speeds 20.72-16= 4.72km/h is the answer