Question

A cyclist is moving with a constant velocity of 10.8 km per hour a long straight road another cyclist starts from rest and moves along the same direction with constant acceleration of 3 metre per second square if both start from the same point after travelling what distance will they meet again

Answer 1

Given that,

Velocity = 10.8 km/hr

Acceleration = 3 m/s²

We need to calculate the time

Using equation of motion

$v=u+at$

Put the value into the formula

$10.8\times\dfrac{5}{18}=0+3\times t$

$t=\dfrac{10.8\times5}{18\times3}$

$t=1\ sec$

We need to calculate the distance at they meet again

Using formula of distance

$v=\dfrac{d}{t}$

$d=v\times t$

Put the value into the formula

$d=10.8\times\dfrac{5}{18}\times1$

$d=3\ m$

Hence, The distance at they meet again is 3 m.

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Topic : kinematics

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