Question

a cyclist is moving with a constant velocity of 10.8 kmph along a straight road. Another cyclist starts from rest and moves along the same direction with a constant acceleration of 3m/s^2.If both start from the same point,after travelling what distance will they meet again?​

Answer 1

Given:

Velocity = 10.8 km/hr

Acceleration = 3 m/s²

To Find:

Distance at which they will meet again

Solution:

Taking the equation v = u + at

Substituting the values

10.8 x 5/18 = 0 + 3t

t = 10.8 x 5 / 18 x 3

t = 54/54

t = 1

Now,

v = d/t, thus

d = 10.8 x 5/18 x t

= 54/18

= 3

Answer: The distance they will meet again is 3m