A cyclist is moving with a speed of 14m/s.he starts accelerating with a rate of 6m/s^ and acquired the speed of 18m/s.calculate what distance did he move in accqiuring that speed?
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Distance covered by the cyclist is 10.66m/s
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Answer:using third equation of motion we can solve the question
Explanation:V×v=u×u+2as
18×18=14×14+2×6s
324=196+12s
128= 12s
S=10.666
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