Question

A cyclist is moving with a speed of 18 km/h, his speed is :

Answer 1

Answer:

Given that v=18km/h=5m/s, μ=0.1 and R=3m

assume that mass of vehicle is m

as the diagram(FBD) shows, if centrifugal force F applying on cycle is more than static friction f then the cyclist will slip down while taking turn

N=mg...(1)

f=μN...(2)

from above two equations

⇒f=μmg=0.1×m×10=m

and ⇒F=m

R

v

2

=m

3

5

2

=8.33×m

we can see F≥f so the cyclist will slip down

solution