Question

A cyclist is moving with a speed of
$6 {ms}^{ - 1}$
As he approaches a circular turn on the road of radius 120m, he applies brakes and reduces his speed at a constant rate of
$0.4 {ms}^{ - 2}$
.The magnitude of the net acceleration of cyclist on circular turn is?​

Answer 1

Answer:

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U=14M/S

A=6M/S^2

V=18M/S

V=U+AT

18=14+6T

18-14=6T

4=6T

T=4/6

S=UT+1/2AT^2

S=14*4/6+1/2*6*(4/6)^2

S=28/3+2

S=34/3

S=11.3 M

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