A cyclist is pedalling his cycle at the constant velocity of 3 m/s. He applies brakes and stops the cycle in 6 s. what is average force of brake if mass of cycle and cyclist together is 80 kg.
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Answer:
-40 kg m/s
Explanation:
given,
u=3m/s
v=0m/s (because cycle stops)
m=80kg
as we know that a= v-u/t
=0-3/6
= -1/2
by Newton's second law of motion
F = m×a
=80× -1/2
= -40 kg m/s.
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