Question

a cyclist is riding along at a constant velocity of 15 miles per second then he accelerates at a uniform rate of 50 m per second squared over a distance of 64 m how long did he accelerate for​

Answer 1

Given:-

• Initial Velocity = 15m/s

• Acceleration = 0.15m/s²

• Distance travelled = 64m.

To Find:-

• Time the cycle accelerated.

Formulae used:-

• S = ut + ½ × a × t²

Where,

• S = Distance
• u = Initial Velocity
• a = Acceleration
• t = Time

Now,

→ S = ut + ½ × a × t²

→ 64 = (15) (t) + ½ × 0.15 × t²

→ 64 = 15t + 0.25

→ 15t + 0.25t² - 64 = 0

→ 0.25t² + 15t - 64 = 0

→ 0.25t² + 16t - t - 64 = 0

→ ( t - 4) (t + 64) = 0.

So, t - 4 = 0 → t = 4.

The Cycle Accelerates for 4second.