a cyclist is travelling at 15 m/s. She applies brakes so that she does not collide with a wall 18m away. What deceleration must she have?
Answers
Answered by
18
Hey dear here is your answer!!!!!!
u= 15m/s
v= 0
a= ?
s= 18m
From 3rd equation of motion;
Substitute the values ....
0-225= 2× a× 18
-225/36= a
a= -6.25
Therefore it must have 6.25 deacceleration ....
Hope it helps u dear....☺️☺️☺️☺️
u= 15m/s
v= 0
a= ?
s= 18m
From 3rd equation of motion;
Substitute the values ....
0-225= 2× a× 18
-225/36= a
a= -6.25
Therefore it must have 6.25 deacceleration ....
Hope it helps u dear....☺️☺️☺️☺️
kevinujunioroy492d:
i wrote that by mistake
Answered by
6
here final velocity will become 0
and acceleration =?
distance =18m
using equation
v=0
-u^2=2a×18
-225=2×a×18
-75=2×a×6
a=-75÷12
a=-25/4
a=-6.25m/s^2
and acceleration =?
distance =18m
using equation
v=0
-u^2=2a×18
-225=2×a×18
-75=2×a×6
a=-75÷12
a=-25/4
a=-6.25m/s^2
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