A cyclist is travelling at 20m/s .She apply break so that does not collide with a wall 18m away. What retardation must she have
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Step-by-step explanation:
By using the equation of motion
v=u+at
By substituting the given values in the above equation
15=6+105t
Then the time is0.0857sec
The distance covered is given as
S=ut+21at2
S=6×0.0857+21×105×(0.0857)2
S=0.514+0.385
The distance covered is0.899m
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Step-by-step explanation:
A cyclist is travelling at 20m/s .She apply break so that does not collide with a wall 18m away. What retardation must she have
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