Question

A cyclist moves from a certain point X and
completes one revolution around a circular path
of radius 'r'. The distance travelled and
magnitude of displacement of the cyclist are
respectively
a) 2r, πr c)2πr, zero
b) π/2, 2π d) r, 2r​

Answer 1

(C) 2πr and zero is correct becoz tthe distance travelled is equal to the circumference of the cycle wheel and the magnitude of displacement is zero as it will co.e back to its orignal position.

hope it help ..

Answer 2

The distance traveled and magnitude of displacement of the cyclist is (c) 2πr, zero.

Given: A cyclist completes one revolution around a circular path of radius 'r'.

To Find: The distance traveled and magnitude of displacement of the cyclist.

Solution:

• We know that displacement is the shortest path to be traveled by an object to reach from one point to another. It is a vector and can have positive, negative, or zero values.
• We know that distance is the region covered by an object along the path of motion, It is always positive.

• The perimeter of a circular path is its circumference which is given by the formula,

        Displacement = 2πR                                              ...(1)

where R = radius of the circular path.

Coming to the numerical, it is said that a cyclist completes one revolution around a circular path of radius 'r'.

So, from (1) the distance covered by the cyclist is the circumference of the circular path.

∴ the distance covered = 2πr  

Now, since the cyclist reaches the same point from where he started after completing one revolution, the displacement is zero.

Hence, the distance traveled and magnitude of displacement of the cyclist is (c) 2πr, zero.

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