Question

A cyclist moves in velodrome of radius of 80 m. If the coefficient of friction is 0.25 then the maximum speed which the cyclist can take a turn whiteout leaning in wards is

Answer 1

Nahi aata...... Chala ja yaha se

Answer 2

Answer:

Explanation:

To take turn centripetal acceleration will be provided by frictional force

∴ (mv2 )/ r=μN

∴ v2=rμg -- eq(1)

Here radius of circular track 'r'=80 m

Coefficient of friction μ=0.25

gravitational acceleration 'g'=10 m s-2

Substituting above values in eq(1) we get

v=22.3 m s-1

but if g=9.8

then v=21.9