Question

A cyclist moves on straight path starts accelerating. In time 10 s, it has 72 km/h speed then its

acceleration is ____.

(A)7.2 m/s2

(B) 120 m/s2

(C) 2 m/s2

(D) 12 m/s2​

Answer 1

Answer:

72km/h = 20 m s ^-1

acceleration = Vf-Vi/t

where Vf is final velocity and Vi is initial velocity and t is time.

a = 20/10 = 2m/s^2

if Vi=0