Question

A cyclist moves with constant speed 5m 's along eastward for 2 seconds and along southward for 2 seconds.Then he moves alomg west for one scoond and finally along andi-west for sqrt(2) seconds.Find (a) Distance and displacement of cyclist for whole joumey. (b) Average speed and average velocity for whole journey (c) Average acceleration of cyclist for whole joumey.

Answer 1

Given:

Speed of cyclist is constant = 5m/s

He moves East for 2 seconds,south for 2 seconds,then moves west for one second and finally anti-west for $\sqrt{2}$ seconds

Solution:

First,please find below the uploaded PDF for a clear and pictorial explaination then you can get the answers of nthe questions

(a) We got Distance travelled by the cyclist = 32.071m

    and displacement of cyclist for whole journey = 12.761m

(b) Average speed = (Total distance)÷(Total time of journey)

    Total time = 2+2+1+$\sqrt{2}$ = 6.414 seconds

    Average speed = $\frac{32.071}{6.414}$ = 5 m/s

   ∴Average speed = 5 m/s

   Average velocity =(Displacement)÷(Total time of journey)

                                = $\frac{12.761}{6.414}$

                                = 1.98m/s

    ∴Average velocity = 1.98 m/s

(c) Average acceleration of cyclist is zero

   Acceleration = (Final velocity - Initial velocity)÷(Time)

                         = (5 -5)÷(6.414)

    Acceleration= 0

415eb57386f4fdcdc28953a8c4c44415.pdf