Question

A cyclist moving along circular path of radius 70m completes one round in 11s calculate average speed and magnitude of average velocity.

Answer 1

Answer:

average speed = 40m/s

average velocity= 0

Explanation:

average speed = distance travelled/time taken

= 2π×70m/11s

= 2×22/7×70/11

=40m/s

average velocity = displacement/ time taken

= 0/11 =0

Answer 2

The average speed and magnitude of average velocity are 39.98 m/s and 0 respectively.

Explanation:

It is given that,

Radius of the circular path, r = 70 m

Time, t = 11 s

At the end of one complete round, the displacement of the cyclist is equal to 0. Average velocity is given by :

Average velocity = displacement/time taken = 0

For average speed,

$v=\dfrac{2\pi r}{t}$

$v=\dfrac{2\pi \times 70}{11}$

v = 39.98 m/s

So, the average speed and magnitude of average velocity are 39.98 m/s and 0 respectively. Hence, this is the required solution.

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