Physics, asked by gagandeepjadhav9799, 1 year ago

A cyclist moving at a speed of 20 m/s takes a turn, if he doubles his speed then chance of overturn(a) is doubled (b) is halved(c) becomes four times (d) becomes 1/4 times

Answers

Answered by ankurbadani84
5

Answer:-

tan θ = v^2/rg where ‘v’ is the velocity , ‘r’ is the radius of the curve and ‘g’ is the force of gravity

In other words , tan θ ∝ v^2

So angle is directly proportional to square of speed.

So when speed in doubled , angle becomes 4 times.

So correct answer is (c) becomes four times .

Answered by nalinsingh
4

Hey !

Explanation

When the cyclist takes a turn, then centripetal force acts on the cyclist.

     ∴  F = mv²/r

(or)       F ∝ v²

Now, if velocity is doubled, the centripetal force will become four times. Therefore, the chance of overturning is 1/4 times.

OPTION :- (D) Becomes 1/4 times.

Good luck !!

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