Question

A cyclist moving on a circular track of radius 100m completes half a velocity a revolution in one minute.what is his average velocity

Answer 1

A cyclist moving on a circular track of radius 100m. (r = 100 m)

Distance complete in one revolution = Circumference of a circle

{ Circumference of circle = 2πr }

Distance covered by cyclist = 2 × 22/7 × 100

= 4400/7

= 628.57 m

Also given that, it completes the one revolution in one minute.

Time (t) = 1 min = 60 sec

Average speed = (Total distance)/(Total time)

= 628.57/60

= 10.47 m/s

Average velocity = (Total displacement)/(Total time)

For circular track displacement = 0 m

= 0/60

= 0 m/s

Therefore, the average velocity of the cyclist is 0 m/s.

Answer 2

Answer:

⋆ DIAGRAM :

$\setlength{\unitlength}{1mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\put(25,30){\line(5,0){20}}\put(25,30){\circle*{1}}\put(29,26){\sf\large{100 m}}\end{picture}$

$\rule{150}{1}$

• Displacement is a Vector whose length is the shortest distance from the initial to the final position.

• As Here we have Circle, So whenever we will start from any point, we will end up finishing there only & Displacement will be Zero.

$\boxed{\bf{\mid{\overline{\underline{\bigstar\:Average\:Velocity\:of\:Cyclist :}}}}\mid}$

$:\implies\sf Average\: Velocity=\dfrac{Total\: Displacement}{Total\: Time}\\\\\\:\implies\sf Average\: Velocity=\dfrac{0\:m}{1\:minute}\\\\\\:\implies\sf Average\: Velocity=\dfrac{0\:m}{60\:sec}\\\\\\:\implies\underline{\boxed{\sf Average\: Velocity=0\:m/sec}}$

⠀

$\therefore\:\underline{\textsf{Average velocity of Cyclist will be \textbf{0 m/sec}}}.$