Question

A cyclist moving on a circular track of radius 100m completes half a velocity a revolution in one minute.what is his average velocity​

Answer 1

The average velocity of the cyclist is 0 m/s.

Explanation :

Given :

A cyclist moving on a circular track of radius 100 m.

The distance complete in one revolution equals to Circumference of a circle.

It completes the one revolution in one minute.

To Find :

The average velocity​.

Solution :

As given,

The distance complete in one revolution equals to Circumference of a circle.

So we know,

Circumference of circle = 2 πr

Therefore,

Distance covered by cyclist -

$\implies \sf 2\times \dfrac{22}{7} \times 100\\ \\ \\ \implies \sf \dfrac{4400}{7}\\ \\ \\\implies \sf 628.57 m.$

It is also given,

Time = 1 min = 60 sec

We know :

$\bigstar\;\boxed{\bf Average\;Speed = \dfrac{Total\;distance}{Total\;time.}}}$

So,

$\implies \sf \dfrac{628.57}{60}\\ \\ \\ \implies \sf 10.47 m/s.$

Now,

$\bigstar\;\boxed{\bf Average\;Velocity = \dfrac{Total\;Displacement}{Total\;Time}}}$

Circular track displacement = 0 m.

So,

$\implies \sf \dfrac{0}{60}\\ \\ \\ \implies \sf 0 m/s.$

Therefore, the average velocity of the cyclist is 0 m/s.

$\rule{300}{1.5}$

$\bigstar\;\underline{\underline{\bf Diagram\; :}}}}$

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Answer 2

Answer:

$\bigstar\fbox{\sf Average\:velocity\:of\:a\:cyclist = 0\:m/s}$

Step-by-step explanation:

★ Given :

• Radius of a cyclist moving on a circular track = 100 m
• Completes a half velocity in = 1 minute (time)

★ To Find,

• His average velocity

★ Solution,

• Circumference of circle = 2πr

☞ Now, distance covered by the cyclist :

→ 2 × 22/7 × 100

→ 4440/7

→ 628.57 m

• Average speed = Total distance/Total time

☞ Time is also given, 1 minute = 60 seconds

→ Average speed = 628.57/60

→ Average speed = 10.47 m/s

• Average velocity = Total displacement/Total time

☞ For a circular track, the displacement will be 0.

→ Average velocity = 0/60

→ Average velocity = 0 m/s

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