Question

a cyclist moving on a straight road covers a. distance 6km with speed 4m/s and 4km with speed 2.5m/s the average speed of cyclist is​

Answer 1

Answer:

3.27m/s

Explanation:

avg speed = total distance / total time

d1=2km=2000m

d2=4km= 4000m

total distance= 2000+4000= 6000

time= distance/speed

t1= 2000/4=500s

t2= 4000/3= 1333.3

total time= 500+1333.3= 1833.3

avg speed= 6000/1833.3=3.27m/s

Answer 2

SOLUTION

GIVEN

A cyclist moving on a straight road covers a distance 6km with speed 4m/s and 4km with speed 2.5m/s

TO DETERMINE

The average speed of cyclist

EVALUATION

Here it is given that a cyclist moving on a straight road covers a. distance 6km with speed 4m/s and 4km with speed 2.5m/s

For distance of 6 km :

Speed = 4 m/s

Distance covered = 6 km = 6000 m

Time taken

$\displaystyle \sf{ = \frac{6000}{4} \: \: sec}$

$\displaystyle \sf{ =1500 \: \: sec}$

For distance of 4 km :

Speed = 2.5 m/s

Distance covered = 4 km = 4000 m

Time taken

$\displaystyle \sf{ = \frac{4000}{2.5} \: \: sec}$

$\displaystyle \sf{ = 1600 \: \: sec}$

Calculation of average speed :

Total distance covered

= 6 km + 4 km

= ( 6000 + 4000 ) m

= 10000 m

Total time taken

= ( 1500 + 1600 ) sec

= 3100 sec

Hence the required average speed

$\displaystyle \sf{ = \frac{Total \: distance \: covered }{Total \: time \: taken } \: \: }$

$\displaystyle \sf{ = \frac{10000 }{3100 } \: \: } \: \: m/s$

$\displaystyle \sf{ = 3.23 } \: \: m/s \: \: (approx)$

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