Question

A cyclist moving towards right with an acceleration of 4 m/sec^2 at t=0, he has travelled 5m moving towards the right at 15 m/s. What will be his position at t=2 seconds?
A. 36
B. 38
C. 41
D. 43

Right answer is D.

Data: a= 4m/s^2, d= 5m, v=15 m/s,
t= 2 seconds, d=?
Solution: d=vt+1/2 at^2
d=15(2)+1/2 (4)(2)^2
d= 30+1/2 (4)(4)
d= 30+16/2
d= (60+16)/2
d= 76/2
d= 38
d=38+5=43 meters

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Answer 1

Explanation:

using motion second equation

s=ut+1/2at^2

s=15*2+1/2*4*4

s=30+8

s=38

now added distance already covered 5m

so 38+5=43

D )43 correct

Answer 2

Explanation:

D. 43

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