Question

a cyclist moving towards right with an acceleration of 4m/s at t =0 he has travelled 5m moving towards the right at 15 m/s what will be his position At t = 2 sec​

Answer 1

Explanation:

1. at t= 0, acceleration is 4m/ss, then he traveled a distance of 5m and finished with a velocity of 15m/s after that first sprint

2. One wants to know where would the cyclist be in 2 seconds FROM THE START at t=0.

Using vv=uu +2as = 15*15 =uu+2.4.5 hence starting velocity/speed =u= sqrt 185

Using v=u+at from the start then the final velocity = sqrt185 +4.2= 21.6

The distance covered from the start is

(13.6+21.6)/2 = average speed times 2 seconds = 35.2 metres

From zero speed, the cyclist must have been on the road for 5.4 seconds accelerating at 4m/ss and covered a total distance of 58.32 metres

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