A cyclist moving with a speed of 14m/s. He starts accelerating with a rate of 6m/s.and acquired the speed of 18m/s. Calculate what distance did he move in acquiring that speed
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Answer:
U=14M/S
A=6M/S^2
V=18M/S
V=U+AT
18=14+6T
18-14=6T
4=6T
T=4/6
S=UT+1/2AT^2
S=14*4/6+1/2*6*(4/6)^2
S=28/3+2
S=34/3
S=11.3 M
Explanation:
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