Question

A cyclist moving with a speed of 14m/s. He starts accelerating with a rate of 6m/s.and acquired the speed of 18m/s. Calculate what distance did he move in acquiring that speed

Answer 1

Answer:

U=14M/S

A=6M/S^2

V=18M/S

V=U+AT

18=14+6T

18-14=6T

4=6T

T=4/6

S=UT+1/2AT^2

S=14*4/6+1/2*6*(4/6)^2

S=28/3+2

S=34/3

S=11.3 M

Explanation: