A cyclist moving with a speed of 8 m/s has a kinetic energy of 1500 J. What is
the mass of the cyclist?
Answers
Given :
- Speed of the cyclist is 8 m/s
- Kinetic energy of the cyclist = 1500 J
To find :
- The mass of the cyclist
Solution :
The relation between mass , kinetic wnergy and velocity is given by ,
We have ,
- v = 8 m/s
- KE = 1500 J
- m = ?
By substituting the values ,
∴ The mass of the cyclist is 46.87 kg
Answer:
Given :
Speed of the cyclist is 8 m/s
Kinetic energy of the cyclist = 1500 J
To find :
The mass of the cyclist
Solution :
The relation between mass , kinetic wnergy and velocity is given by ,
\boxed {\rm{KE = \frac{1}{2}M {V}^{2} }}
KE=
2
1
MV
2
We have ,
v = 8 m/s
KE = 1500 J
m = ?
By substituting the values ,
\begin{gathered} : \implies \rm \: 1500 \: J= \frac{1}{2} \times M \times (8 \: m {s}^{ - 1} ) {}^{2} \\ \\ : \implies \rm \: 1500 \: J= \frac{1}{2} \times M \times 64 \: m {}^{2} {s}^{ - 2 } \\ \\ : \implies \rm \: 1500 \: kgm {}^{2} {s}^{ - 2} = 32 m {}^{2} {s}^{ - 2} \times M \\ \\ : \implies \rm \: 1500 \: kg \: \cancel{ {m}^{2} {s}^{ - 2} } = 32 \: \cancel{ {m}^{2} {s}^{ - 2} } \times M\\ \\ : \implies \rm \: 1500 \: kg = 32M \\ \\ : \implies \rm \: \frac{1500 \: kg}{32} = M \\ \\ : \implies \rm \: M = 46.87 \: kg\end{gathered}
:⟹1500J=
2
1
×M×(8ms
−1
)
2
:⟹1500J=
2
1
×M×64m
2
s
−2
:⟹1500kgm
2
s
−2
=32m
2
s
−2
×M
:⟹1500kg
m
2
s
−2
=32
m
2
s
−2
×M
:⟹1500kg=32M
:⟹
32
1500kg
=M
:⟹M=46.87kg
∴ The mass of the cyclist is 46.87 kg