a cyclist of mass 40kg increases his speed from 18kmph to 72kmph.If the mass of his bicycle is 60. Find the ratio of his initial and final kinetic energy
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Hi ,
Here's the answer:-
Initial kinetic energy = 1/2 mv² = 1/2 × (40+60) × 18² = 1/2 × 100 × 18 × 18 = 9× 18× 100 = 259200 J
Final kinetic energy = 1/2 mv² = 1/2×100×72×72 = 36×72×100 =43200 J
So, ratio = 16200 J : 259200J = 1:16
So, finally, the answer is 1:16
HOPE IT HELPS (^_^)
Here's the answer:-
Initial kinetic energy = 1/2 mv² = 1/2 × (40+60) × 18² = 1/2 × 100 × 18 × 18 = 9× 18× 100 = 259200 J
Final kinetic energy = 1/2 mv² = 1/2×100×72×72 = 36×72×100 =43200 J
So, ratio = 16200 J : 259200J = 1:16
So, finally, the answer is 1:16
HOPE IT HELPS (^_^)
supersonu:
No, 1/2 is impossible
finl kinetic energy is suppose to be 259500 not 43200
dear, i need a brainliest answer urgently
no
yes but u r wrong
omg i hv just calculate
it is 259200
the answet is 1:16
ok i wud have edited
plz give me brainliest
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