Question

a cyclist pedalling with 9kmph takes a sharp circular turn of radius 5 m then the angle should the cyclist bend towards the circular path is (take g=10 m/s)​

Answer 1

Answer :

Speed of cyclist = 9km/h = 2.5m/s

Radius of circular path = 5m

Acc. due to gravity = 10m/s²

We have to find angle of cyclist with vertical$.$

◈ Bending of cyclist !

In order to take a circular turn of radius r with speed v, the cyclist shoulf bend himself through an angle Φ from thr vertical such that

• tanΦ = v²/rg

➝ tanΦ = v²/rg

➝ tanΦ = 2.5²/(5×10)

➝ tanΦ = 2.5/5 × 2.5/10

➝ tanΦ = 1/8

➝ Φ = tan$^{-1}$(1/8)

☃ God_Bless :)