A cyclist pedals from his house to his college at a speed of 10 KMPH and back from the college to his house at 15 KMPH. Find the average speed.
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Answer:
Average speed = (10 + 15) /2 = 25/2 = 12.5 KMPH
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Step-by-step explanation:
Given A cyclist pedals from his house to his college at a speed of 10 KMPH and back from the college to his house at 15 KMPH. Find the average speed.
- Let the distance from house to college be m km
- Let the time taken from house to college be t1
- So we have time taken from house to college at a speed of 15 km/hr So m = 10 x t1-------1
- m = 15 x t2-------2
- So from 1 and 2
- 10 t1 = 15 t2
- t1 = 15 / 10 t2
- So we get average speed = total distance / total time = 10 t1 + 15 t2 / t1 + t2
- = 10 x 15 / 10 t2 + 15 t2 / 15/10 t2 + t2
- = 30 t2 / 15 t2 + 10 t2 / 10
- = 300 t2 / 25 t2
- = 12 km / hr
Therefore the average speed is 12 km/hr
Reference link will be
https://brainly.in/question/18486682
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