A cyclist plans to cover the distance of 240 km. He calculated that if he is going to ride 8.4 km/h faster than planned, he will cover the same distance 105 minutes earlier. At what speed did he originally plan to ride?
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Answer:
. A cyclist plan to cover the distance of 2 40 km, right, suppose this is the starting point and this is the end point and this distance is to 40 kilometers. Suppose he thinks that he will go with the speed. V kilometer, but I was So the time it will take distance divided way Velocity which is 2 45 p. Now when He ride 8.4 km, but our faster than he planned, that means now speed is We plus 8.4 kilometers per hour. Now the new time You will be equal to 2:40 the right way. We plus 8.4 bait. No, it is given that he will cover the same distance 105 minutes earlier. That means the new minus the old should be equal to 105 minutes. That means in power, it will be called to 105 by 60. This will be t minus staining because if he goes with the faster speed He will take less time. Right? So T -10, you should be equal to 105 minutes. So I will convert it into Second, so I divided by 60. So this will be equal to 2 40 HIV minus 2 45. We plus 8.4. It is a call to 1.7 1.75. Okay, no, we will solve this. So, so this is two for TV -2 for TV will cancel each other. So this is very square plus 8.4 and two V should we call to 2016 divided by 1.75. So we can write we square plus 8.4 weeks minus. So we will solve this quadratic equation and we get The speed he planned is a call to 30 kilometre barrage.