Question

A cyclist riding with speed 5 meter per second braked with uniform decceleration and stopped in 3m .hew long did she take to stop?

Answer 1

Answer:

Explanation:

Uniform Acceleration Equations

V = Vo + At

D = 1/2(At²)

Eliminating t yields, D = (V-Vo)²/2A

So in this case using equation 3. we get: D = 3m Vo=5m/d, V = 0

3 = 25/2A so A = 25/6 now to check. Using equation 1. solve for t. Note that since this is a deceleration the sign of A is negative. t = 30/25 = 1.2 Now using the value of t and the value of A solve for D using equation 2.

1/2(25/6)(1.2²)= 3 Q.E.D The deceleration is 25/6 m/s²