A Cyclist rolls down a hill. He starts from rest and after 8s he is travelling at 13.6m/s. What is his acceleration?
Answers
Answer :
- Acceleration of the cyclist starting from rest and moving with a Velocity of 13.6 m/s after 8 s is 1.7 m/s².
Explanation :
Given :
- Time taken by the cyclist, t = 8 s
- Final velocity of the cyclist, v = 13.6 m/s
- Initial velocity of the cyclist, u = 0 m/s
[Note : Since the cyclist is starting from rest, the initial velocity of the cyclist will be taken as zero]
To find :
- Acceleration produced by the cyclist, a = ?
Knowledge required :
First equation of motion :
⠀⠀⠀⠀⠀⠀⠀⠀⠀v = u + at
Where,
- v = Final velocity
- u = Initial velocity
- a = Acceleration
- t = Time Taken
Solution :
By using the first equation of motion and substituting the values in it, we get :
⠀⠀=> v = u + at
⠀⠀=> 13.6 = 0 + a × 8
⠀⠀=> 13.6 = 8a
⠀⠀=> 13.6/8 = a
⠀⠀=> 1.7 = a
⠀⠀⠀⠀⠀⠀⠀⠀⠀∴ a = 1.7 m/s²
Therefore,
- Acceleration produced by the cyclist, a = 1.7 m/s²
Explanation:
Acceleration = 1.7 m/s²
- Time (t) = 8 s
- Initial velocity (u) = 0 m/s [starting from rest]
- Final velocity (v) = 13.6 m/s
- Acceleration (a) = ?
Let's take analysis of the situation !
There is a cyclist who rolled down a hill, starting from rest he traveled at a velocity of 13.6 m/s in 8 seconds. Now, we have to calculate the magnitude of acceleration.
Let's find now !
We remember the formula of acceleration i.e,
(Now, just put all the given values)
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》We can find acceleration by Newton's first law of motion also i.e, v = u + at. The ans will be same only.
Hope it helped you dear...