Question

A cyclist speeding at 18
km/h on a level road takes a sharp circular
turn of radius 3 m without reducing the
speed. The co-efficient of static friction
between the tyres and the road is 0.1. Will
the cyclist slip while taking the turn ?​

Answer 1

Given that v=18km/h=5m/s, μ=0.1 and R=3m

assume that mass of vehicle is m

as the diagram(FBD) shows, if centrifugal force F applying on cycle is more than static friction f then the cyclist will slip down while taking turn

N=mg...(1)

f=μN...(2)

from above two equations

⇒f=μmg=0.1×m×10=m

and ⇒F=m

R

v

2

=m

3

5

2

=8.33×m

we can see F≥f so the cyclist will slip down