Question

A cyclist speeding at 72kmph on a
level road takes a sharp circular turn
of radius 2 m without reducing
speed. The coefficient of static
friction between tyre and road is 0.2.
The cyclist slip while taking the turn​

Answer 1

Explanation:

$vmax = \sqrt{mrg } \\ 0.2 \times 2 \times 9.8 \\ 1.979ms^{ - 1}$

72km/s= 20m/s

Answer 2

$vmax = \sqrt{mrg}$

$0.2 \times 2 \times 9.8$

$= {1.979}^{ - 1}$

$72km/s \: = 20m/s$