Question

A cyclist start from rest and moves with uniform acceleration of 0.2 m /s after 2 minute find the velocity of the cyclist and the distance covered.​

Answer 1

Explanation:

initial velocity (u) =0,acceleration(a) =0.2m/s^2,time(t)=2minutes =120 seconds

by substituing values in formula v=u+at

v=u+at

v=0+0.2(120)

v=0.2(120)

v=24

THEREFORE YOUR ANSWER IS 24m/s

I hope you are satisfied by my answer.

Answer 2

Answer:

24,12

Explanation:

V=u+at

=0+0.2(120)

=24m/s

S=(v^2-u^2)/2a

=(576-0)/48

=12m

HOPE THIS WILL HELP YOU.

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