Question

a cyclist start together for a point A, 20 km away. One cyclist goes steadily at 10 kmph while the other goes faster but with constant speed. The faster cyclist reches the point A and returns to meet the slower cyclist exactly half way to the point A. The speed of the faster cyclist was

Answer 1

the right answer is 30 km/hr

Answer 2

In the same time,Distance covered by faster cyclist is 30km(20+10) and the distance covered by slower one is 10km.
Given
Speed of slow cyclist ,V1=10
Distance of slow cyclist, D1= 10km
Speed of faster cyclist = V2
Distance of faster cyclist,D2 = 30km

Equating time
D1/V1= D2/V2
10/10 = 30/V2
V2 = 30
option C is correct