Question

a cyclist starting from rest accelerates at 10m/s^2 for 10 second and travels at uniform velocity for the next 20 second. What is the total distance travelled in this interval​

Answer 1

Explanation:

Initial velocity (u) = 0m/s

Acceleration (a) = 10m/s²

Time (t) = 10 sec

Using first equation of motion:-

⇢v = u + at

⇢ v = 0 + 10 × 10

⇢ v = 100m/s

Distance for first 10 sec

⇢ s = ut + ½ at²

⇢s = 0 × 10 + ½ × 10 × (10) ²

⇢ s = 0 + 5 × 100

⇢ s = 500m

Distance for first 10 sec = 500m

Distance for next 20 sec

⇢ s = ut + ½ at²

⇢ s = 0 + ½ × 10 × (20) ²

⇢ s = 5 × 400

⇢ s = 2000m

Distance for next 20 sec = 2000m

Total distance = 500 + 2000 = 2500m

∴ Total distance travelled = 2500m