A cyclist starts from centre O of a circular park of radius 1 km, reaches the egde and the cycles along the circumference and returns to to the centre O along OQ. If the round trip takes 10 mins calculate the average speed.
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Answer:
Since the initial position coincides with the final position. So, the net displacement of the cyclist = zero
Average speed of the cyclist =
Total time taken
Total distance travelled
=
10
OP+PQ+QO
km min
−1
=
20
π+4
×60kmh
−1
=21.4kmh
−1
Explanation:
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