Question

A cyclist starts from the centre O of a circular park of radius 1 km reaches the edge P of the park, then cycles along the circumference and returns to the centre along QO as shown in figure. If the round trip takes 10 min, what is the (a) net displacement (b)average velocity and (c) average speed of the cyclist?

Answer 1

Hii dear,

# Answer-
a) Net displacement = 0
b) Average velocity = 0
c) Average speed = 5.95 m/s

## Explaination-
# Given-
r = 1 km = 1000 m
t = 10 min = 600 s

# Solution-
a) As particle reach its original position after journey, net displacement will be zero.
s = 0

b) As displacement is zero, average velocity will also be zero.
v = s/t = 0

c) Average speed is given by,
v' = path length/t
v' = (r+πr/2+r)/t
v' = (2×1000+3.14×1000/2)/600
v' = 3570/600
v' = 5.95 m/s.
Hence, average speed of cyclist is 5.95 m/s.

Hope that is helpful...

Answer 2

Answer:

# Answer-

a) Net displacement = 0

b) Average velocity = 0

c) Average speed = 5.95 m/s

## Explaination-

# Given-

r = 1 km = 1000 m

t = 10 min = 600 s

# Solution-

a) As particle reach its original position after journey, net displacement will be zero.

s = 0

b) As displacement is zero, average velocity will also be zero.

v = s/t = 0

c) Average speed is given by,

v' = path length/t

v' = (r+πr/2+r)/t

v' = (2×1000+3.14×1000/2)/600

v' = 3570/600

v' = 5.95 m/s.

Hence, average speed of cyclist is 5.95 m/s.

Hope that is helpful...

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