a cyclist travel a distance of 3 km from P to Q and then travel a distance of 4 km at right angle to PQ find distance and displacement
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D= √(3²+4²)=√25=5km is the displacement
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Distance- 3+4 =7 km , because we can add total covered path to determine distance
Displacement - √3^2+4^2= 5 km , because the shortest path covered by body is taken to determine displacement.
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