Question

A cyclist travel a distance of 4 km from A to B and then moves at a distance of 3 kilometre at right angle to AB find his resultan displacement and total distance travelled​

Answer 1

Explanation:

AC square = ab square + bc square

AC square = 4 square + 3 square

AC square = 16+9

AC square = 25

AC = √25

AC = 5

so the disp

so the displacement is 5 km