Question

A cyclist travelled distance 1km in the first hour 0.5km second hour 0.3km in third hour . Find the average speed cyclist in meter per second

Answer 1

Answer:

The average velocity is 0.6 km/hr and 0.167 m/s. Hence, The average velocity is 0.6 km/hr and 0.167 m/s.

Answer:

The average velocity is 0.6 km/hr and 0.167 m/s.

Explanation:

Given that,

Distance in one hour = 1 km

Distance in second hour = 0.5 km

Distance in third hour = 0.3 km

We know that,

Average speed = total distance /total time

(I). Average speed in km/hr

v = \dfrac{D}{T}v=

T

D

v = \dfrac{1\ km+0.5\ km +0.3\ km}{3\ hr}v=

3 hr

1 km+0.5 km+0.3 km

v = 0.6\ km/hrv=0.6 km/hr

(II). Average speed in m/s

v = 0.6\times\dfrac{5}{18}v=0.6×

18

5

v = 0.167\ m/sv=0.167 m/s

Hence, The average velocity is 0.6 km/hr and 0.167 m/s.

Or,

we know that average speed =sum of speeds at different intervals / hours.

so,

$$\begin{lgathered}average \: speed = \frac{1 + 0.5 + 0.3}{3} \\ = \frac{1.8}{3} \\ = 0.6 \: kmph.\end{lgathered}$$

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