A cyclist travelling at 14km/h takes 6 hours 45 minutes to cover a certain journey. How long would it take a car travelling at 52km/h to cover the same journey ? Give your answer correct to the nearest minute.
Answers
Answer:
Step-by-step explanation:
Given:
(1/4)th of a journey travel with speed = 16 km/h
(3/4)th of a journey travel with speed = 8 km/h
Total time taken to cover the journey = 14 hours
Formula used:
Time = Distance/Speed
Calculation:
Let the total distance is x km
⇒ [(x/4)]/16] + [(3x/4)/8] = 14
⇒ (x/64) + (3x/32) = 14
⇒ (x + 6x)/64 = 14
⇒ 7x/64 = 14
⇒ x = (14 × 64)/7
⇒ x = 128 km
Total distance travel by train is 128
v1 = 14 km/ h = 14/60 = 7/30 km / min.
v2 = 52 km/ h = 52/60 = 26/30 km / min.
t1 = 6 hrs. 45 minutes = 405 minutes
t2 = x min.
s = v1 t1 = (7/30 * 405) km
Since, the car covers same distance, so,
s = v2 t2 = v1 t1
26/30 * x = 7/30 * 405
x = 109.03 min.
∴ It takes 109 mins.(approx.) for the car to cover the distance.
Hope It Helps :)